For sure I don’t know what the Amps reading on the meter will mean but I guess if it goes up or down from the normal value then there is something wrong. Perhaps if you have the time you can explain to me what the reading of the Amps means. I thought I mentioned before that when I searched ebay for a Voltmeter I found much more combo meters (Volts / Amps) than just Voltmeters and I thought why not get a combo? They are almost the same price.
When you scope the current to a power supply for the steppers, you will basically get an AC current at a high frequency relative to the power line. It draws pulses, so it really isn't DC. DC with ripple, maybe.
For AC currents and/or voltage, you have to go back to Calculus. There is an Integral formula for average of a periodic function and it may look like this TRMS = sqrt(AVERAGE(X^2))). You square it, make it positive, then average it, and then square root it. It makes the value positive.
Now I need pretty pic and have to really do some work to get the concept across. Let's suppose I had a resistor with a constant V and a constant I. What I want is a number that when an arbitrary AC waveform is applied, I get the same value when a steady DC value of current is applied. It's doable, but it's expensive.
"Most" people are dealing with the powerline (50 or 60 Hz) and DC voltages < 24 VDC for the most part. The AC part of the multimeter has been fudged. I kinda full wave rectifies the input and charges a capacitor then it divides by some some number that makes a sine wave of say 120 VAC read 120 AC. So, it works for most people.
The numbers read by these simple meters can be WAY off.
Another way of looking at AC and DC for a fixed R is that the power dissipated for V * I is always the same if it is AC or DC.
This will fail if the waveform is not a sinusoid for AC. So a 12 V sinusoid and 12 V DC applied to 1 ohm resistor, the resistor will dissipate P = V*I watts or 12.
For a non-sinusoid, or an inductive load or RF frequencies even this breaks down.
For sinusoidal current and sinusoidal voltages P = V(t)*I(t) * pf. Here, we introduce the concept of Power factor or the pase difference of the voltage and current components. I always have to look up the concepts. Inductance moves it one way and capacitance moves it another. pf = cos(theta).
the OP said:
Accuracy is not that important, we are talking here hobby stuff but of course accuracy has a wide range so lets say if the reading is out by 10-15% it should be ok. I would say that these meters should be able to do better than that
It will be all over the map and dependent on speed, and again, that's what I'm asking you why measure it?
the OP said:
Sorry for the link with the220VAC meter, I notice it later but I was looking on the wiring diagram only to see if I understand it
You have to look carefully.
the OP said:
So is it a good idea to measure the Amps only on the power supply unit?
I've been asking that question all along. Why not propose it to the CNC group. If the discussion gets out of hand I might join.
That was a very lengthy thread re Joe, good job
I think there is like 1200 posts in that thread. It would take a significant time to read it. My link brought you in at the tail end.
Sorry for the problems you had with the computer and flood, hope all is ok now. We have a powerful wind storm today here and the lights are flickering so I hope I don’t loose the power or burn something. Never went to Linux myself but I did give it a try years ago and decided to stick with Windows
Problems at home have been cascading and are still spiraling downward.
Regarding your fiend in Australia setting the tool to the ORG position, on my previous cnc I used 3 limit switches and along with the Mach3 software (controlling the cnc) I was able to home the machine on every start
X, Y and Z org sensors are different. Usually the org sensor is more precise.
What I'm talking about is basically the tool Z origin relative to the workpiece. For instance, tis video:
A fixed precision insulated metal plate. The tool, makes contact from "ground" to the block, thus you can set the Z of the tool to the workpiece height. Say it's contact + 0.200", if the block is 0.200 thick and Z down is positive. You always have to do edge and center finding and the CNC can automate that process.
the OP said:
Never order anything from Aliexpress, would you recommend them to buy the meter? I was thinking of this meter
**broken link removed**
Nicolas
Probably not a bad choice. You will need a say 5V power supply. Maybe order one for me (Northeast US) to be able to play with. You might even need two power supplies per meter.
With both ebay and aliexpress and Chinese parts, expect the only documentation is the documentation on the ebay and aliexpress website.
The first step would be to measure the voltage to ground on both sides of the shunt with a voltage applied, but no load, I would expect that voltage to be zeroish
The next step would be to take a 0-75mV DC impedance source (power supply) and a variable series resistor and to vary the series resistor until it reach 36.5 mV. Take out the pot and measure the resistance.
That's the basic info that's needed before continuing. You might have to cut a trace or something.
So, off the top of my head, possibly two 5 V power supplies that are isolated for each meter. One has to power the meter because of the 30 V limitation.
I'm SUSPECTING that you can supply a signal from COM to IN+ of 0-75 mV and my initial question is the input Z of that point and whether Com is connected to the external power supply common.
We also don;t know the range of the current calibrate control.
We might find out that using a 12 V supply for the meter and a 12 to +-5 for the signal conditioning.
I just don' know what to expect.
Worst case, I would expect to use an external power supply for the meter for the 30 V limitation.
and possibly an isolated DC-DC converter e.g.
https://www.digikey.com/product-detail/en/NKA0505SC/811-1419-5-ND/1926980 +5 and -5 DC-DC converter and a hall effect sensor + some sort of "glue electronics". The +- V dual supply may be the way to go.
The "glue electronics" might consist of a voltage divider (5V to 75 mV) and an Instrumentation AMP such as an AMP02:
https://www.google.com/url?sa=t&rct...Nl9ydgOhe-PUzTg&bvm=bv.55819444,d.cWc&cad=rja
So, as you can see it's a PITA to make a high side current monitor.
What the Chinese are supplying is a dual voltmeter, one with a 50 V scale and one with a 75 mV scale, so there is lots of reuse. The cost is in the real estate (the PCB), the case and the power supply.