c++ convert argv[1] to a char array

[danielsmusic]

is this posible, looking on google turned up nothing.

 

[spirosd]

main(int argc, char *argv[])
{
 ......
}

Now, the separators for argv are os dependant but typically they are tabs or spaces so

one, two, and three => four strings
one,two, and three => three strings

If you want number parameters you would convert the string into a number using atoi() atof() ...

HTH
Spiros

 

[MikeHibbett]

Can you explain your question a different way?

It is just that argv[1] is already a char array.

What is it that you wish to do?

Can you give us an example of your problem?

Mike.

 

[akg]

is this posible, looking on google turned up nothing.

argc contains the nof arguments passed and argv[0]...argv[n] contains the different arguments.and itself char*

 

[danielsmusic]

well i wrote this fuction that needs a char array to work but just passing argv[2] doesnt work i wont compile i sayes it cannot convert it

 

[Styx]

whats the code?