Thank you, NG, Steve.
Let's talk about it in little detail. Yes, you have
talked about it before but I didn't really get your point then. Moreover, I understand that my queries are somewhat confusing but that's the best I can do at this moment. Seriously this part is really baffling me. I would request you to read my queries at least twice so that you can understand my confusion at least to some degree. Thanks.
Q1: To start with, I don't even understand
this circuit. I have assumed that when a battery is being charged up and the current flowing into the battery is above certain value, the relay keeps connection to the battery bank. When the current falls below a certain below which would mean battery is fully charged then the relay makes connection with the dummy load. Is that how it works? What's about those LEDs? When will yellow LED be lit?
Q2: Now I will try to understand what you have been trying to warn me about. Let's say that the 12 V battery has entered
Stage 2. In stage 2, the voltage remains constant but current flowing into the battery gradually starts decreasing. The battery limits the current flowing into it or the system should be able to regulate the flow of current into the battery. I think if the voltage is kept constant then the battery can limit the current itself. Right?
Q3: I have assumed that the battery is limiting the current flowing into it. Please have a look on
this figure. The tracker which is functioning at maximum power is continuously pumping current into the converter. Let's say that the voltage at the input terminal of the converter is 17V which will be Vmp because the tracker is working at MPP and the voltage at output terminal is almost 14.4V. If the MPP tracker is continuously pushing more energy (in form of current) then this energy needs to go somewhere. But where does it go? It looks like that this continuous throwing of energy into the converter will tend to increase the overall voltage until the voltage of the converter is also 17 V. Let's see how. Let's suppose the tracker is continuously supplying an average of one ampere into the converter. This might force more current into the battery than is actually allowed or recommended, and further this might raise the overall voltage of converter by raising the voltage of the battery little by little until the voltage of 17 V is reached. This might lead to two things. The battery gets damaged or capacitor gets exploded or both gets damaged. Do you agree with me, at least to some degree?
Q4: Okay. The battery might be damaged but why the capacitor would explode. The Cin of the tracker doesn't explode when it is charged up to Voc which is greater than Vmp; in this case Vmp is 14.4 V. Further, when the voltage of converter is reached 17 V, the whole system will stop functioning assuming the battery is not present at the output terminal because when the voltage of Cout is 17 V, the tracker is no longer able to throw in any more energy. Do I have it correct?
Q5: You can notice once a battery enters
stage 3, its current falls to zero and its voltage also falls somewhat. Does this voltage falls on its own, or, we need to reduce it to that level for some reason?
Regards
PG