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Adding the ability to measure ac ammeter in dt830d multimeter

electronium

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Hello guys, another day and another challenge... we all know how practical and affordable the dt830d series multimeters are and available for a repairman, engineer, technician, but this multimeter can measure It doesn't measure the ac current, how can we do something with a pre-circuit in the multimeter or outside the multimeter to measure the ammper ac current and mA ac?
I put the schematic diagram for you in the picture below
312577.png

m830b-schematic-diagram.gif
 
Last edited:
Use a suitable known value "shunt" resistor in line with the circuit, and measure the voltage across that.

eg. A one ohm shunt would give 1V per amp.
A ten milliohm shunt would give ten millivolts per amp.

For in-circuit / PCB use, they are generally just precision low value resistors. For higher currents and stand-alone use, they are often four terminal devices, so the measuring points are separate from the power terminals.


 
Use a suitable known value "shunt" resistor in line with the circuit, and measure the voltage across that.

eg. A one ohm shunt would give 1V per amp.
A ten milliohm shunt would give ten millivolts per amp.

For in-circuit / PCB use, they are generally just precision low value resistors. For higher currents and stand-alone use, they are often four terminal devices, so the measuring points are separate from the power terminals.


Every multimeter has shunt resistance, but this model of multimeter cannot measure amperes and mA ac. The challenge is actually this.
 
If you have noticed, the shunt is the same in all multimeters that measure ac and dc amperes, but there is a different selection selector, one selector measures dc and the other selector measures ac...now we wanted to add a circuit to the prop and multimeter. provide ac and mA for us!?
 
Now I checked the test with a 1n4007 diode, I put the series test lamp in the circuit and the ammeter of the dt832 multimeter, the amperage is measured, but due to the power loss compared to the diode, it does not show 0.39A, instead it shows 0.22A.
Vrms=230v
r filament lamp stat off = 33 ohm
i = 0.39A
i with diode =0.22A
Related video analysis and testing
 
Every multimeter has shunt resistance, but this model of multimeter cannot measure amperes and mA ac. The challenge is actually this.
That's why you need a separate, EXTERNAL current shunt!

eg.

Current Shunts.jpg


For low power electronics, you can just use a normal resistor, eg. one ohm or 100 milliohm.

Or you could use an add-on current clamp, eg:


Just using external rectifiers can work under some circumstances, but not where the voltage drop they add will affect the circuit, or if the current is too high.
 
This time, testing the small 15w 220v refrigerator lamp with the mA section of the dt832 multimeter, with and without tricks, and as you can see, the mA ac section works well, now it is enough to have two diode bridges and input and output terminals for the ampere and milliampere sections. If we consider inside the multimeter or outside the multimeter, the work is done
video test mA ac with dt832
 

Your link is not doing much for me? What am I supposed to see or hear?

Before we start talking about a shunt and measuring the AC voltage drop across a shunt maybe we should look at the AC Voltage ranges of the meter. The meter only has 200 and 500 VAC ranges with 100 mV and 1.0 volt resolution. It's only an inexpensive meter and adding a shunt sans amplification is not going to get you anything. Typical shunts only output 50 mV or 100 mV full scale.

Next even meters that measure AC voltages and currents unless specified otherwise only actually average and display RMS values. This is fine for pure sine waves but that's as good as it gets, average responding RMS indicating. Good meters are RMS responding RMS indicating. Here nor there but something to consider.

You could use a peak detector which will charge to the peak value of the AC waveform and then just do the basic math.

I would still be curious as to what I am supposed to take away with your link?

Ron
 

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