Ok, if there's no base current then the collector current is same as emitter current then:
Voltage across 1k8 is (3.3mA x 1k8)= 5.04V
Vc is (10V-5.04V)= 4.06V
Vce is (4.06V+0.6V)= 4.66V Solved!
Few questions again:
¤ Base is connected directly in a voltage which is 0.6V higher than the emitter, which means there is base current too. But why we ignore here the important base current? Because it is 3.3mA divided by 100 (beta) and it is so small, so?
¤ There's 4.66V difference between Emitter to Collector voltage. Which things determined the CE voltage? Due to 'turn ON resistance' of the transistor? Or are there ani fix voltage drop (like BE has 0.6V fix drop) across Coollector to Emitter?