Better Idea...
Thanks to all of you for helping me.
From all the suggestions I got, I think this is close enough to a better circuit I came across :
This circuit employs capacitive reactance for limiting the current flow through the LEDs on application of mains voltage to the circuit. If we use only a series resistor for limiting the current with mains operation, the limiting resistor itself will dissipate around 2 to 3 watts of power, whereas no power is dissipated in a capacitor. The value of capacitor is calculated by using the following relationships:
XC = 1/(2πfC) ohms —————(a)
XC = VRMS
/I ohms ———— (b)
where XC is capacitive reactance in ohms,C is capacitance in farads, I is the current through the LED in amperes, f is the mains frequency in Hz, and Vrms is the input mains voltage. The 100-ohm, 2W series resistor avoids heavy ‘inrush’ current during transients. MOV at the input prevents surges or spikes,
protecting the circuit. The 390-kilo-ohm, ½-watt resistor acts as a bleeder to pro-vide discharge path for capacitor Cx when mains supply is disconnected. The zener diode at the output section prevents ex-
cess reverse voltage levels appearing across the LEDs during negative half cycles. During positive half cycle, the voltage across LEDs is limited to zener voltage. Use AC capacitors for Cx. Filter capaci-
tor C1 across the output provides flickerfree light.
Is it all right now ? or are there still many errors to be corrected.
What can be substituted for MOV 270/20, if I don’t get hold of it. ?
Thanks
Zmint. (Trying to gain, a positive charge from electronics)