A light load LED driver

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OK, both you all. All I did was build an emitter follower amplifier and replace RE with an LED. That simple. If I drive the base with the supply, the base bias will do the current limiting.

But with no degree of control, and no idea what the current might be.

The purpose of my post was to show that (A) I personally have not seen this done before and so I wanted to demonstrate that the common transistor switch configuration (driving a Xsistor into hard saturation) is not the only method to drive an LED.

You've not seen it because it's such bad design - no problem with the LED in the emitter, but put a resistor in series with it - it then makes a working circuit.


Yes, no problem at all, just add the RESISTOR - which will reduce the load even further. But I fail to see how the load is significantly less than having the LED (and resistor) in the collector? - assuming the gain of the transistor is 200, the LED current will be 0.5% more with it in the emitter, not terribly significant.
 
But I fail to see how the load is significantly less than having the LED (and resistor) in the collector?

For one thing, it is a current amplifier and not a voltage amplifier. So there is less load on the voltage which is something I needed for the circuit.

Yes, no problem at all, just add the RESISTOR

Yes boss....
 
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