most motherboards today have around 4-5 power slots for fans. cpu, ram,and 2 or 2 for the caseYou must have a pretty nice system to use 4 fans
You said your a noob, so I'll just say this in case you don't know:
Any motherboard you buy today will be able to control at least 2 fans on its own, the CPU fan, and case fan. It will also vary at least the CPU fan depending on the temperature.
And another option: If you have modern fans that are PWM'ed to speed up/ slow them down, you can use this:
View attachment 42378
Newegg.ca - Rosewill 12" PWM Splitter Model RCW-FPS-401
It takes the power of the PSU, and the PWM signal from the mobo to vary all of your fans.
I agree and that is why in a previous post I covered the following:The only problem is that with a conventional pot, the current my not be high enough for the fan to operate, you need to add a transistor to increase the potential current.
When the pot is adjusted for 0 Ω obviously there will be no current limiting. As the resistance of the pot is increased there will be a voltage drop across the pot and current limiting will ensue. The fan will subsequently slow down. Now there is a small problem with all this.Typically an 80 mm fan running at 12 volts draws about 170 mA (.170 Amp) give or take. Matter of fact the same holds about true for 120 mm and larger case fans. Therefore we can use that approximation or let's say the typical fan running on 12 volts won't draw a current exceeding 200 mA or .2 Amp. The current draw will also be proportional to the speed of the fan so as we reduce fan speed the current will reduce proportionally.
I don't think it is wise to run the fans on less than about 6 to 7 volts. They will actually run fine at those voltages but may not start spinning at the lower voltages. Therefore if while running you decrease the fan voltages below about 6 to 7 volts the next time you start the computer the fans may not start spinning. So we want to be able to run the fan on about 6 to 12 volts meaning the max voltage drop we want is about 6 volts.
Well if we want to drop 6 volts or so in the circuit and the current is 200 mA we can divide the current into the voltage (6.0 / .200 = 30) so we want a 30 Ohm resistor. So we could use a 30 Ohm variable resistor or a pot in the neighborhood of 25 to 30 Ohms give or take and the pot should be rated at 2 watts minimum.