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I have a small query ,suppose i have sync the inverter(i.e freq,voltage) output with the grid ..in this case line voltage and generated voltage become same then how will i identified which is input voltage and which is generated voltage..
Thanks in advance
Try update topic.
I build this inverter test version (on a table as a Barbe), my mechanic power meter show - it really work!
Electronic power meter (it cant show direction, becoase use both) show max 120 W (primary from PV 17V, 8A).
But! C1 (I use 680u*50V) very hot One pcs shooted
The ESR (Equivalent Series Resistance) of a capacitor has a lot to do with how much they will heat up in use and where C1 is located in the circuit it's handling a very high ripple voltage which means it's also handling a very high average current in and out of it as I stated in post 3 "The Capacitor" description.
If you can not find a suitable capacitor in the specified range, ~5uF per input amp, that has a low ESR value you can cheat by going up to a higher working voltage rating, as I referenced to using s 250 volt rated unit in a 12 volt system, or use multiple smaller value capacitors in parallel.
On my larger higher voltage GTI units I have used nonpolar AC rated motor run type capacitors being they are specifically designed to work in very high ripple current applications.
So given that if you are using a 680 uF 50 volt capacitor on a 17 volt 8 amp input I can totally see why it blows up. The uF value is way way too big (17X) and the voltage rating is way too low( .2x).
This and re-reading the instructions should help you out considerably on C1 overheat issues.
I try to make one grid inverter but the main problem is how to eliminate the one of the output not to be live . because both wires are live. I did not try yours disign.