ok, think I'm ready to make a fool of myself again
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so if we know the voltage of the componant we are using + the reading should always equal the V potential, no matter how many componants are fitted
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Then here
there are different rules which are confusing me
From second link, but not on first
where: V = voltage in volts (V)
I = current in amps (A)
R = resistance in ohms () or: V = voltage in volts (V)
I = current in milliamps (mA)
R = resistance in kilohms (k)
For most electronic circuits the amp is too large and the ohm is too small, so we often measure current in milliamps (mA) and resistance in kilohms (k). 1 mA = 0.001 A and 1 k = 1000 .
The Ohm's Law equations work if you use V, A and , or if you use V, mA and k. You must not mix these sets of units in the equations so you may need to convert between mA and A or k and .
So where I had my original reading of 470 ohms, the actual resistor I brought was 470 ohms which would be 0.470 of a Kohm instead I should of related it to 4.7 Kohm
So I ended up with 29. mA short instead of 2.9 mA
Edited your post 45 times......EEK!
**broken link removed** Thanks for trying to make it easier to understand
So when I get calculations in future, they need to be done in Kohms & not ohms
or have I totally missed it again
**broken link removed** why do I get a gut feeling I'm not there yet, why don't other pages tell you to work it in Kohms
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Doh
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If you are calculating A you use ohms
If you are calculationg mA you use Kohms
Just noticed.........sorry, can I go & hide now
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So does that mean I'm there now for this box, just looking at prices of resistors, they are 26p each at local store or £1.90 for 100 online
whats that in $ for you, hold on $0.40 at local store for one or $2.98 for 100
So if I need to order some, is there any other parts I can order to play with?