PG1995
Active Member
Hi
Please have a look on the attachment. I have integrated the "solution" which is a differential equation to see if I get back y just out of curiosity. As you can see, I ended up with:
1: y = -c|x^3|, or, 2: y = c|x^3|
The original form was y=c1*x^3. So which form should I use, "1" or "2"? I think it's "2" because the original form didn't have a negative sign "-". But what about the absolute value? Please help me with it. Thanks a lot.
Regards
PG
Please have a look on the attachment. I have integrated the "solution" which is a differential equation to see if I get back y just out of curiosity. As you can see, I ended up with:
1: y = -c|x^3|, or, 2: y = c|x^3|
The original form was y=c1*x^3. So which form should I use, "1" or "2"? I think it's "2" because the original form didn't have a negative sign "-". But what about the absolute value? Please help me with it. Thanks a lot.
Regards
PG