ElectroNewby
Member
I'm supposed to resolve sin(π+t) and it should equal -sin(t). I'm lost
I know that :
sin(-θ) = -sinθ
and that -sinθ = cos(θ + π/2)
...and that sin(θ+α) = sinθcosα + sinαcosθ
But honestly, I'm not able to demonstrate that sin(π+t) = -sin(t)
Can anybody help me ??
thank you so much
I know that :
sin(-θ) = -sinθ
and that -sinθ = cos(θ + π/2)
...and that sin(θ+α) = sinθcosα + sinαcosθ
But honestly, I'm not able to demonstrate that sin(π+t) = -sin(t)
Can anybody help me ??
thank you so much