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GETTING STEADY

Discussion in 'General Electronics Chat' started by niga, Jun 7, 2005.

  1. eblc1388

    eblc1388 Active Member

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    Because of the current cource, which cannot be open circuited, I drafted two cases for an initial condition.

    The diffficulties only occurs when t=0.
     

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  2. niga

    niga New Member

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    THANKYOU LOTS AND LOADS!!![/color]

    I really hope this is the end of my doubts.It is in this section atleast :)wink:)heheh
    It feels good to know there are people out there who really help!

    Best regards
    niga
     
  3. ljcox

    ljcox Well-Known Member

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    There is no need to open or short the current source.

    The current source is a step function that goes from 0 to I at t = 0.

    I(t) = I u(t)

    This is clearer if you solve the problem using Laplace Transforms. See attachment.

    Len
     

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  4. dave

    Dave New Member

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  5. niga

    niga New Member

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    Hi len,

    U have gone through a lot of trouble drafting all this for me.I am sure many others also found your informations useful.Thankyou so much again.

    Sincere regards-niga
     

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