Converting CCS to XC8

[Muscleman]

Hello people, I'm doing a project based on this one:**broken link removed**
but then the code provided by the author is based on ccs, but i need to convert it to xc8
here is the code

#include <16f877a.h>
#include <defs_877.h>
#use     delay(clock=10000000)
#fuses   hs,nowdt,nocpd,nolvp,noprotect
#byte portb=0x06
#byte portd=0x08
#bit  clock=portd.6
#bit  data=portd.7
unsigned int8 i,j,index1,n,
addr[11]={0xEA,0xEA,0x2A,0x2A,0x2A,0x2A,0xAA,0x82,0xFF,0xFF,0xFF},
cont[11];
void main()
{
     set_tris_b(0x00);
     set_tris_d(0x00);
    while(1)
    {
        for(n=0;n<=99;n++)
       {
            data=1;
            for(i=0;i<=7;i++)
            {
                clock=1;
                portb=addr[i];
                delay_ms(1);
                clock=0;
                data=0;
            }
        }

        for(j=0;j<=10;j++)
        {
            cont[j]=addr[j];
        }
        for(j=0;j<=9;j++)
        {
            addr[j]=cont[j+1];
        }
        addr[10]=cont[0];

    }
}

here is my attempt at converting to xc8

#include <xc.h>
#include <htc.h>
#include <stdint.h>
#pragma config WDTE=OFF
#pragma config LVP=OFF
#pragma config PWRTE=OFF
#pragma config DEBUG=OFF
#pragma config FOSC=HS
#define __delay_ms(x) _delay((unsigned long)((x)*(_XTAL_FREQ/10000000.0)))
#define   _XTAL_FREQ 10000000

int main(void)
{

uint8_t i,j,index1,n,
addr[11]={0xEA,0xEA,0x2A,0x2A,0x2A,0x2A,0xAA,0x82,0xFF,0xFF,0xFF},
cont[11];
     TRISB=0x00;
     TRISD=0x00;


    while(1)
    {
        for(n=0;n<=99;n++)
       {
          PORTDbits.RD7=1;


            for(i=0;i<=7;i++)
            {
               PORTDbits.RD6=1;

                PORTB=addr[i];
                __delay_ms(1);
                PORTDbits.RD6=0;
                PORTDbits.RD7=0;


            }
        }

        for(j=0;j<=10;j++)
        {
            cont[j]=addr[j];
        }

        for(j=0;j<=9;j++)
        {
            addr[j]=cont[j+1];
        }
        addr[10]=cont[0];

    }
}

I'm not sure how to convert
#byte portb=0x06
#byte portd=0x08
#bit clock=portd.6
#bit data=portd.7
I would appreciate some help thanks.

 

[NorthGuy]

Just remove these.

Note that the original programs sets D6 at the beginning of the inner loop while you set D7.

 

[Muscleman]

Just remove these.

Note that the original programs sets D6 at the beginning of the inner loop while you set D7.

What will I remove?

 

[NorthGuy]

What will I remove?

These things you're asking about:

I'm not sure how to convert
#byte portb=0x06
#byte portd=0x08
#bit clock=portd.6
#bit data=portd.7

 

[Muscleman]

ok thanks, about the other statement or my conversion of data=1 or 0 to PORTDbits.RD7=1 or clock=1 or 0 to PORTDbits.RD6=1 is it correct? because I uploaded to the program to my pic (actual circuit) but the dot matrix shows only blinking lights

 

[NorthGuy]

Yes. The original program is setting data (D7) to 1 for the first execution of the inner loop and to 0 for the rest of them, and cycles the clock (D6) every loop. Is that what you're trying to accomplish?

 

[Muscleman]

Yes sir, I just based it on the original program of the author, other than that are there any flaws in my conversion that could not make the desired output( driving dot matrix)?

 

[NorthGuy]

Aside of these lines, not present in the oringinal:

PORTB=0x06;
PORTD=0x08;

which are not harmful, and the fact you set D7 instead of D6 in the inner loop, the programs look identical to me.

 

[Muscleman]

Aside of these lines, not present in the oringinal:

PORTB=0x06;
PORTD=0x08;

which are not harmful, and the fact you set D7 instead of D6 in the inner loop, the programs look identical to me.

Ooops, I just noticed I set d7(data)=1 instead of d6(clock)=1 in the for i loop , I edited the code now to which I removed:
PORTB=0x06;
PORTD=0x08;
edit:I had included earlier that code^ because i thought I would convert this one also:
#byte portb=0x06
#byte portd=0x08

 

[Muscleman]

Thanks so much for help!! it's now working in the proteus isis simulation, all I have to do now is connect it again in the actual circuit, but tomorrow is the day I can test because someone's taken care of the pcb development today