I am studying amplifiers from a book and at the end of the chapter are questions. One that I am stuck on is
If an amplifier has a power gain of 25 and input and output resistance of 600ohms what is the input voltage if the output voltage is 10v?
Now the answer in the book is 2v but I cannot locate anywhere how to calculate this correctly.
Power gain is pVout * pIout / pVin * pIin so I thought that by using ohms law for the output I could do
pIout=Vout / Rout which is 600ohms = 10/600 = 17mA
The formula for current gain is Iout / Iin, I know the Iout (17mA) but cant calculate Iin as I only know the 600ohm input resistance and not the voltage.
Am I going the correct way about this and if so what is next please?
Thanks
Graham
If an amplifier has a power gain of 25 and input and output resistance of 600ohms what is the input voltage if the output voltage is 10v?
Now the answer in the book is 2v but I cannot locate anywhere how to calculate this correctly.
Power gain is pVout * pIout / pVin * pIin so I thought that by using ohms law for the output I could do
pIout=Vout / Rout which is 600ohms = 10/600 = 17mA
The formula for current gain is Iout / Iin, I know the Iout (17mA) but cant calculate Iin as I only know the 600ohm input resistance and not the voltage.
Am I going the correct way about this and if so what is next please?
Thanks
Graham