Why Wire Bonding uses Au(gold)?

[mailrapid]

As we know, when it comes to wire bonding, we can image that it is "Au" bonding.

Byt why not uses Ag or Cu bonding instead of Au?

 

[JimB]

Probably because gold does not react with other elements, so it does not corrode or deteriorate.

Same reason for using gold plated pins in connectors.

JimB

 

[Speakerguy]

Are you talking about wire bonding in the silicon-to-package sense?

If so, they also use aluminum as well as gold.

 

[Super_voip]

gold can be extruded in extremely fine wire, directly at the workstation.

 

[mailrapid]

thank you all.

 

[HD ELEKTRONİK]

R = (Ro x L) / S

 

[Roff]

R = (Ro x L) / S

OK, that's too cryptic for a simpleton like me. Why did you post that equation in this thread?

 

[Styx]

its the resistance equation


Yer gold is used, easy to work with. So is aluminium, easy to work with. You should see the machines in action as they fly along knitting the bondwires down

 

[Speakerguy]

I only have experience doing manual wire bonding. It is extremely tedious and difficult. I only have about 12hrs experience on the machine though.

Interestingly enough, the bobbins we had (both alu and gold) had expiration dates. Since neither oxidizes indefinitely like copper or iron, I always thought it odd they had 'throw-away' dates on them. But extruding it right at the unit fixes that I guess. Any reason why they have to do it that way?

 

[Hero999]

I'm surprised that you would throw the gold away; surely it's worth recycling.

 

[Speakerguy]

I guess 'use by' would be more accurate

 

[HD ELEKTRONİK]

Why Au , why Cu or Al not use.

OK, that's too cryptic for a simpleton like me. Why did you post that equation in this thread?

For example ;

Edit:Fig. in :mu: m

 

[HD ELEKTRONİK]

Also ;
If , this IC's make Cu or Al use ,
Wires is to have more section required.
This is IC's impossible Nano Technology or Micro Technology.

 

[Roff]

For example ;

Edit:Fig. in :mu: m

Why are different cross sectional areas used for the 3 types of wire?