You're talking about the time constant - not the time delay.kinjalgp said:The time delay i.e. Charging Time (t)= 0.693 * R * C
therefore , t = 0.693 * 10 * 10 = 69.3 Seconds
For a cap charging from zero volts to Vf,kinjalgp said:Ok I got it but what about your time constant i.e. R*C
Which one is correct 0.693*R*C or just R*C ?
The time constant is the product of C and R. I had not seen a reference to 0.693 before and did not realise its significance until Ron's reply.kinjalgp said:Ok I got it but what about your time constant i.e. R*C
Which one is correct 0.693*R*C or just R*C ?
Ron's second sentence is the application of time constant that I remember.Ron H said:....In other words, it takes 0.693RC seconds for the capacitor to charge to half the supply voltage (0.5*Vf).
Using the first equation, when t=RC (one time constant), the cap will have charged to 0.632*Vf