What is the easiest way to create a register from an input serial command?

Hi All,
What is the easiest way to create an 8-bit register from an input serial command consisting of 8 bits per byte from a single digital I/O pin on a PIC16F684?

I have a slave device sending an 8 bit serial command to RA2 of a PIC16F684. The pic tests the pin 8 times for a high or low voltage. I would like to store the entire byte of data within one register address. Any thoughts?

I was thinking of making a temporary address such as Bit7, Bit6, Bit5...Bit0 and storing the temporary value of 1 or 0 and manipulating the data from there.

Any Ideas?

Thanks!

Test the bit & set or clear the carry bit in the STATUS register & use RLF or RRF command.Do Rotate 8 times to generate the register.

Check my PIC RS232 tutorials, it's really simple - you're making it sound far harder than it is.

Thank you guys, Nigel - Which tutorial # is it? # 7?

Steve311 said:

Thank you guys, Nigel - Which tutorial # is it? # 7?

Click to expand...

Yes, #7 - it's based on a VERY old Parallax application note, which used their own assembler.

Great, Looks like this will help a lot. Thanks for your help and nice tutorials.

Steve