Combine the 2 and 1 Ohm resistors into an equivalent resistance. Redraw the circuit noting that a wire that shorts across a resistor eliminates it from consideration. You will find the current source has two separate resistances across it. Combine them for an equiv resistance and then calculate the voltage caused by 2A of current.
If you don't get it by tomorrow, I'll post the answer.
i agree with you, all resistors are in parallel
all you have to do is to resolve to resistors from left to right
i think that will help you get total the voltage
find your way from there
For the final time, the resistors are in parallel, see Wikipedia for working out the total resistance then calculate the voltage using Ohm's law. Resistor - Wikipedia, the free encyclopedia
Try this: designate the long wire that wraps around the outside of the schematic as ground and then redraw the schematic. One side of the current source connects to the ground line, one side of every resistor connects to ground. I believe you will see how the current source is connected across all the resistors in parallel. You will also notice one of the resistors is connected to two different points of the ground line, so it has no current through it and can be eliminated.
Please show the circuitry in the simple way. What I get stucked is the current source location and the top & Bottom loop separated with a single wire, what will affect the total current?
Note that the signs across the resistor are opposite to the supply so the voltage will b negative. Don't allow this to confuse you, just put a - sign in front of your answer.
What happened to the 1 Ohm parallel the lower right hand 2 Ohm?
there is a series/parallel combo of 2 + (1//2) = 2 + (2/3) = 2.6666 Ohm, that should parallel your 3 Ohm and the source?
What happened to the 1 Ohm parallel the lower right hand 2 Ohm?
there is a series/parallel combo of 2 + (1//2) = 2 + (2/3) = 2.6666 Ohm, that should parallel your 3 Ohm and the source?