hi 1982,
From your description it suggests you had connected the meter in series with 10meg resistor.?
The meter has internal resistance, so current will flow through the 10meg and the meters resistance, this current will cause a voltage drop across the 10meg.
eg: assume your meter had a 10meg internal resistance, when connected in series with another 10meg connected to 5V, the meter would read 2.5V.
E