Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

verification problem

Status
Not open for further replies.

bogla

New Member
Here is a problem I'm trying to solve.

RPkA9Sh.jpg





Here is the given solution in my book.

TmHEB8y.jpg



I don't understand that marked area in the solution.

Need help to understand it to move ahead.

Can anybody please explain that in a simpler way?

Thanks
 
Let me try to restate the problem:

1. By definition, A*B=AB + !A!B, where !=not (the * operator is sorta like ex-or)

2. Let C=A*B

3. Verify that A=B*C

4. Substitute A*B for C in the above equation, A=B*A*B, but also put () around the last two terms, so it looks like this: A=B*(A*B)

5. Now use the definition of the connective operator (equ 1) to expand equ 4: A=!B!(A*B) + B(A*B)


ps 50 years as a logic designer, and I never heard of the "connective"
 
5. Now use the definition of the connective operator (equ 1) to expand equ 4: A=!B!(A*B) + B(A*B)

awesome. got this part.

But stuck in the next step here.

Please see this step.

Is it a law ? which law ? or how can we do that step there ?
QfyLGF3.jpg
 
That transition can be shown with a simple two-term, four-square Veich diagram, aka DeMorgan's Theorem
 
Last edited:
Status
Not open for further replies.
Back
Top