Our train just passed each other. I was speaking of wrapping the source wire (carrying 25A) through the CT a second time.
On another note, I'm not following your words, but I do follow the math. The picture shows 50:5 and 5:1000, so 25A source reduces to 2.5A, then 2.5A is reduced by 5:1000 from 2.5A to 12.5mA. The description says "getting another 50:5", by which the 2.5A would be reduced by 50:5 from 2.5A to 0.25A.
That is unless I'm not following something.