In calculus you could be given [latex]y=2x^{3}+3[/latex] and be asked to find the first derivative. It would be [latex]y=6x^{2}[/latex]
KISS said:The weather has to get better for me to attempt this.
KISS said:The impact of this derivative thing is that it changes the phase angle of the voltage when we talk about sine waves. The derivative of the sin(x) is the cos(x), hence you can see a huge phase shift in the voltage.
In the real world, you can't have a pure capacitor. This phase shift makes inductors and capacitors very different from all other electrical components..
The resistor, by creating a load, limits the current. Very important, And by limiting the current, it generates a voltage across itself.
there can never be work being performed (battery connected to a motor) without the flow of current:
Yes, but this is a major breakthrough, that makes all caps/semiconductors 'V' related doesn't it?
The great thing about derivation is that I never could figure out how Newton came up with the concept. For my part I just accepted on faith that it was how it was done and it worked. I'm sure there's a proof of it somewhere, but in the end I didn't care...
Hopelessly pedantic
thereby always causes the voltage to decrease, not generate across the resistor.
so current flow literally means "charge flow flow",
which is redundant and ridiculous
The electrical energy is what ties RLC components together.
Both Newton and Leibniz simultaneously and independently formulated the fundamental concepts of calculus as an effective discipline. The basic concept is not that complex. Archimedes used integral calculus in his geometrical computations. Any good calculus book can show you the derivations of the calculus formulas.
but in the end I didn't care...
Muttley said:& I'm willing to eat humble pie if I'm wrong, but I'll bet my last £ that when I work it out, a derivitive means a point on a graph.lol
Simply, the derivative is the slope at every point on a curve.
Mathematically it's a mess for non-polynomials
and requires a lot of memorization and rules just like algebra.
The derivative is usually taken with respect to something.
If you have an x-y graph
then dy/dx is the derivative of y with respect to x.
The dy can be somewhat thought of as delta y or the change in y over the change in x.
This goes back to the slope at any point definition.
Now with something that Graham is familiar with, his bike.
We have two variables; distance and time.
so if s=DISTANCE, VELOCITY (speed) = [latex]v=\frac{ds}{dt}[/latex] and the second derivative of speed with respect to t is ACCELERATION and the third derivative with respect to speed is the more unknown quantity, the JERK.
ACCELERATION is how fast the speed is changing per unit time. The JERK is how fast the acceleration is changing with time.
So, does this give you an intuitive "feel" for what a derivative is?
ok, you've told me so many times it's a slope.....I believe you, it's a slope, why do we need a slope to measure a curve on a graph, I cannot see the logic in having a slope, can you tell me why we need a slope in the first place
I figured that bit out & looking at CBB's next sim (I am so looking forward to that now) this plane runs at 90degrees to the Y-T graph, but I'm struggling as that would mean your measuring width of something & we aren't are we?
Is dy/dx simply the ends of the tangent line?
but why, what is the difference of having a slope & a point on the curve?
So your not trying to tell me the signal (coiled spring/ my image of wave) has a roundness as this is already covered by the ampitude p-p measurement
cbb said:Then it restarts at "0" degrees all over again for each subsequent cycle.
KISS said:That's wrong. It does start over, but 720
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?