In calculus you could be given [latex]y=2x^{3}+3[/latex] and be asked to find the first derivative. It would be [latex]y=6x^{2}[/latex]
Graham, just for the sake of clarity, this example derivative was calculated by taking the exponent of X (in the first equation), multiplying it times the multiplier of X (2, in this case), reducing X's current exponent by 1, eliminating the constant and putting it all back together as the first derivative Y=6X[SUP]2[/SUP].
The great thing about derivation is that I never could figure out how Newton came up with the concept. For my part I just accepted on faith that it was how it was done and it worked. I'm sure there's a proof of it somewhere, but in the end I didn't care...
Graham, don't miss post #78!!