hi,
As I guess you know, about 1.25V is about the lowest you can output from a LM317.
What I have seen are supplies which have a low voltage zener or 2 or 3 diodes in series at the 0V input end of the supply.
These give about 1.4V thru 2.1V drop along the 0V line, the ADJ of the LM317 is connected to input side of the diodes/zener, so the output of the supply is ~0V thru +V.
hi,
This is a simple way to get close to 0V output.
The regulation is not as good as a direct connection LM317, bit does enable a close to 0V out.
Choose a 1Watt zener also the 220R fixed resistor is required.
Look at the LT3083. It is a little harder to use than the LM317 but can be set to very low voltages!
Input voltage must be less than 23V.
Current 3A. I think there is a 1A version.
Current must be greater than 1mA!
Low dropout 0.3V.
Use only one resistor to set voltage. Can be set to o volts.
See fig. 8 in data sheet.
The zener in the return current path will give poor load regulation. The circuit in the app note uses an extra rail (negative rail) & allows the zener reference to pass a steady current & therefore has better load regulation.
Another way of achieving the 0-5V output is using the attached circuit. The opamp inputs and output must be able to operate close to 0V. A 5V regulator can supply the 5V reference.
The LM317 datasheet shows a way to use a second LM317 in the negative rail to act like a fixed 1.25v zener, to give full adjustment down to zero volts.
The LM317 datasheet shows a way to use a second LM317 in the negative rail to act like a fixed 1.25v zener, to give full adjustment down to zero volts.
hi Roman,
Personally I would go for a second battery in the OP's set up. IIUC he is using a 9V battery.??
If he is not using a battery then a 9Vdc 'wall wart' would give the required offset voltage.
As always we dont know the application, does the OP want the set up for a 'one off' test or does he want to make a 'decent' '0V thru +5V' regulated 1Amp power supply.???
It needs a negative supply for the opamp. Otherwise the output voltage is going to be the 1.25V of the LM317 added to the minimum output voltage of the opamp (which I guess is 1.75V in your case).
If you want to use a single 9V battery, you can use e.g. one of the circuits posted. There's not much headroom if you're using an LM317 & 9V supply: The LM317 needs ~1.7V across it and you need a negative supply 1.25V below the 0V reference which means 8V minimum for 0-5V output, so if the battery's a little flat or the opamps are not ideal, it won't work.