mike_ss said:
So 0v goes into the Emitter of transistor 2 and that is the only thing connected to the negative on the battery.
According to audioguru's circuit, yes.
Then the positive goes through the 470 ohm resistor to the anode of the LED then to the 'touch' switch?
yes
Does anyone have any other easy transistor projects I can try out?
I do. In fact, it is about the most simplest NPN transistor experiment yet. Here is what you do:
1. Connect the NPN's emitter to the anode of an LED.
2. Connect the cathode of the same LED to one end of a 1K resistor.
3. Connect the other end of the 1K to ground (which is 0V).
4. Connect the NPN's collector to +5V.
and try one of the following steps, but do NOT do them both at the same time.
5. Connect the NPN's base to +5V.
6. Connect the NPN's base to +0V.
you will notice that you have made yourself a simple transistor switch.
Also, you will realize that an NPN requires +ve voltage (I think at least 0.65) at it's base to turn on.
AND, you will see why an NPN transistor is two diodes with the anodes connected to each other.