The same tired quesiton about rectification

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Kal_B

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Hello everyone,


I don't know why I still don't get this maybe the formulas are too complicated.

I have 230VAC which I will connect to full wave rectifier, what would the output be without any filters or anything else connected.

I found answers ranging from 230 x 1.414 to 230 x 0.7 and many other formulas.


Thanks
Kal
 
Without a capacitor it will be 230V DC but very bumpy. The bumps will go from 0V to 230*1.414 - the peak voltage. With a capacitor, it will charge to the peak voltage - 230 * 1.414. The 1.414 is the square root of 2.

edit, the 0.707 you've encountered is one over root two and is how you convert the other way.

Mike.
 
Thanks Mike.

To clarify, and please excuse my ignorance, the bumps will go from 0V to 325V that is DC with a ripple?

Thanks
Kal
 
Kal_B said:
o clarify, and please excuse my ignorance, the bumps will go from 0V to 325V that is DC with a ripple?
Click to expand...
Yes, you have a 325V ripple.
The RMS value of this is still 230V.
The average DC value of this is 0.636 of the peak or 207V.
 
What would the frequency of the ripple, does it relate to the frequency of the AC current rectified so if it's 60HZ then the ripple will be at the same rate?

Thanks
Kal
 
Kal_B said:
What would the frequency of the ripple, does it relate to the frequency of the AC current rectified so if it's 60HZ then the ripple will be at the same rate?
Click to expand...

Full wave rectification doubles the ripple frequency, so 120Hz for 60Hz mains.
 
Here's a simulation to show the output from a full-wave rectified output for a 230Vac, 60Hz input (yellow trace).
Note that the output ripple is double the input frequency as Nigel noted, and that the average (DC) output is 204.75V and the RMS output is 227.4V (slightly less than I stated in post #4 due to the forward voltage drop loss of the diodes).

 
Here's a more conventional picture of a bridge rectifier circuit. It's easier to trace what happens when the sine wave is positive or negative.

 
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