terminology question

[irishape]

On this circuit it has 3vpp triangle wave that needs 10vpp. Two resistors, one 30k and 120k which author says gives 10/3 ratio which I assume he arrived at by dividing by 12. Then it says to multiply 3vpp by 10/3 to get 10vpp. He lost me here, any help? Thank you. Yes, I am new at this.

 

[Reloadron]

I don't get it? If for example I add 30K + 120K I get 150K and 30K is 1/5th of 150K. So if I place the 30K (top) and 120K (bottom) in series and apply 10 volts across them the output across the 30K would be 2 volts which is 1/5th of the 10 volts.

Yes, 10/3 = 3.33333 and 3.33333 * 3 = 10. However, and maybe I am missing it, I don't see the connection with the resistor values specified.

Ron

 

[crutschow]

What circuit?

 

[Reloadron]

What circuit?

Dat too!

Ron

 

[irishape]

terminology queation

Okay,what I am using is the 566 VCO chip as in a music making project. This portion of the circuit is about using two discrete transistors as a differential pair. This section is using a pickup from pin 4 on the 566. It is using the 36k and 120k resistors on the IC1a which produces a triangle wave. Then down to the rest of circuit to change to a sine wave. The pin four from 566 is producing 3vpp which we want to up to 10vpp. This is where the author states that the ratio of the resistors create a 10/3 ratio and to get the 10vpp to multiply the 3vpp by the 10/3. The only way I could come up with it is divide 3 into 10 and multiply the 3.3 with the 3vpp which gives you 9.9v. I just was not sure if the slash mark on the 10/3 ratio thing was to be consisdered a divide mark and assume he had rounded off the numbers. The question is, is this the proper way to mark division in electronic work. I probably should have stated it that way first but am trying to be careful. Hope this rambling on explains my question.

 

[alec_t]

3vpp which we want to up to 10vpp

You can't increase a voltage by using just resistors; you need an amplifier.

 

[Reloadron]

Can you post the circuit? That would likely make understanding this much easier for everyone.

Ron

 

[irishape]

Ron, thank you for the help and the interest. It would be pretty hard to get the circuit posted because there is several sections of it. My real question, which I made a mess of aking, was just if the slash mark in 10/3 is to be consisdered a division mark as that was the only way I could make any sense of what he was saying. I am now satisfied that is what he was saying. Thanks again for your help. IA

 

[Reloadron]

I take it to be division as in 10 / 3 = 3.333. Ratio is generally expressed as for example 3:1 meaning a 3 to 1 ratio.

Ron