Richardcavell
Member
Hi,
I've been told that when using the Superposition theorem to analyse a circuit, I should replace all constant current sources other than the one I'm analysing with an open-circuit. But I need to retain the internal resistance of the current source in the circuit. Where does that resistance go, if the current source is replaced with an open?
Richard
I've been told that when using the Superposition theorem to analyse a circuit, I should replace all constant current sources other than the one I'm analysing with an open-circuit. But I need to retain the internal resistance of the current source in the circuit. Where does that resistance go, if the current source is replaced with an open?
Richard