ok.... now i get it.....
I'll summarize the working, correct me where i'm going wrong,ok...
The audio signal from the mic, an AC signal gets AC coupled through C1,R3.. It is given to the inverting amplifier...
Correct
One doubt: the voltage divider using R2,R4 given to the + terminal of the 1st opamp, acts as a reference, right?
Its sets the amp operating point voltage at half the supply voltage.
This is needed as its a AC coupled amp.
Also, if the configuration of the 1st opamp is changed to non-inverting, it wouldn't make any differcnce, right? or it there any reason for it?
It should be a non inverting amp anyway.!
The circuit will need modification
Continuing, the amplified signal from the opamp gets inverted and is AC coupled to the 2nd opamp.
Another doubt: you said, "10K is to reference the 2nd amp input to 0V." but it is given to the +ve terminal itself, so does the -ve terminal has its potential as 0?
The -V of the battery is 0V.
Continuing..... the 2nd opamp responds to +ve half cycles.. producing positive voltage and the necessary current for the transistor.....
Correct
Is the circuit operation correct?