sine wave to sawtooth wave

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mabauti

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I want to convert a signal from 8.5V 60hz sine wave to sawtooth 0-5V wave.

so far I have this :

**broken link removed**


My question is : Is there an easier way to do that?
my final goal is to have a phase control circuit.
 
mabauti said:
I want to convert a signal from 8.5V 60hz sine wave to sawtooth 0-5V wave.

so far I have this :

**broken link removed**


My question is : Is there an easier way to do that?
my final goal is to have a phase control circuit.
If you want to eliminate the transformer and the negative supply, and your load is high impedance (comparator input?), maybe you can use the circuit below.
 

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Last edited:
What if I used the transformer anyway (120VCA>8.5VCA)?

What if I would like to connect the circuit directly to the 120 AC power?
 
mabauti said:
What if I used the transformer anyway (120VCA>8.5VCA)?

What if I would like to connect the circuit directly to the 120 AC power?
Your original schematic implied that you already have an 8.5V peak sine wave. If you are actually getting the 8.5V sine from a transformer connected to the 120V mains, you can still use the schematic I posted. I am posting an alternate version that uses both phases out of the transformer. I show the option of getting your DC power directly from the transformer, which may or may not be useful.
Keep in mind that any of these schemes, including yours, will probably be susceptible to power line (mains) transients, but that may not cause a problem. Phase control, in fact, will tend to put transients on the AC line.
 

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