sin-wave

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stealthelectric

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Hi:
Please see the question attached.

If I find the peak value - √2 x 12.0V = 17.0V (2s.f.)
We have 6 divisions peak-peak, so divide 17.0 by 6 to get 2.8V (2s.f.)

Could somebody please tell me if I have the right solution here?
Thanks
 
The peak voltage calculation is correct.

The peak-to-peak calculation is wrong, it should be double the peak voltage.
 
peak value - √2 x 12.0V = 17.0V (2s.f.)
So, peak to peak = 34.0V
We have 6 divisions peak-peak, so divide 34.0 by 6 to get 5.67V (3s.f.)

Considering the figures given in the question, should I choose 2 or 3 significant figures for the answer?
 
Yes, the peak is three divisions and the peak-to-peak is six divisions.

I don't know how you should round the answer, I used to hate that at school. I generally gave a figure more than what was given to me in the question.
 
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