S stealthelectric New Member Feb 25, 2010 #1 Hi: Please see the question attached. If I find the peak value - √2 x 12.0V = 17.0V (2s.f.) We have 6 divisions peak-peak, so divide 17.0 by 6 to get 2.8V (2s.f.) Could somebody please tell me if I have the right solution here? Thanks
Hi: Please see the question attached. If I find the peak value - √2 x 12.0V = 17.0V (2s.f.) We have 6 divisions peak-peak, so divide 17.0 by 6 to get 2.8V (2s.f.) Could somebody please tell me if I have the right solution here? Thanks
Hero999 Banned Feb 26, 2010 #2 The peak voltage calculation is correct. The peak-to-peak calculation is wrong, it should be double the peak voltage.
The peak voltage calculation is correct. The peak-to-peak calculation is wrong, it should be double the peak voltage.
S stealthelectric New Member Feb 27, 2010 #3 peak value - √2 x 12.0V = 17.0V (2s.f.) So, peak to peak = 34.0V We have 6 divisions peak-peak, so divide 34.0 by 6 to get 5.67V (3s.f.) Considering the figures given in the question, should I choose 2 or 3 significant figures for the answer?
peak value - √2 x 12.0V = 17.0V (2s.f.) So, peak to peak = 34.0V We have 6 divisions peak-peak, so divide 34.0 by 6 to get 5.67V (3s.f.) Considering the figures given in the question, should I choose 2 or 3 significant figures for the answer?
Hero999 Banned Feb 27, 2010 #4 Yes, the peak is three divisions and the peak-to-peak is six divisions. I don't know how you should round the answer, I used to hate that at school. I generally gave a figure more than what was given to me in the question.
Yes, the peak is three divisions and the peak-to-peak is six divisions. I don't know how you should round the answer, I used to hate that at school. I generally gave a figure more than what was given to me in the question.
S stealthelectric New Member Feb 28, 2010 #6 so for the x-direction. I take 1/250Hz=0.004, for the period. Then 0.004/5squares=0.8x10^-3s for the time of one division?
so for the x-direction. I take 1/250Hz=0.004, for the period. Then 0.004/5squares=0.8x10^-3s for the time of one division?
S stealthelectric New Member Feb 28, 2010 #8 thank you hero But do you mean 10^-6? Last edited: Feb 28, 2010