B biferi Member Mar 12, 2014 #1 I know if I have say 3 Resisters in Series and I know they are R1=20 Ohm and R2=20 then the both of them will be 400 Ohm. But if they are in Parallel do I Divide each Resister like so R1=20 Divided by R2=20 then the Total Resistance is 1 Ohm am I right? Please keep it simple but tell me in your own words. Thank you.
I know if I have say 3 Resisters in Series and I know they are R1=20 Ohm and R2=20 then the both of them will be 400 Ohm. But if they are in Parallel do I Divide each Resister like so R1=20 Divided by R2=20 then the Total Resistance is 1 Ohm am I right? Please keep it simple but tell me in your own words. Thank you.
ronsimpson Well-Known Member Most Helpful Member Mar 12, 2014 #2 I know if I have say 3 Resisters in Series and I know they are R1=20 Ohm and R2=20 then the both of them will be 400 Ohm. Click to expand... 20+20=40 But if they are in Parallel do I Divide each Resister like so R1=20 Divided by R2=20 then the Total Resistance is 1 Ohm am I right? Click to expand... . For only two resistors, the unreciprocated expression is reasonably simple: So R1//R2, 20//20 is 10 ohms. "//" = parallel (1/20)+(1/20)=0.05+.05=0.10= (1/0.1) =10
I know if I have say 3 Resisters in Series and I know they are R1=20 Ohm and R2=20 then the both of them will be 400 Ohm. Click to expand... 20+20=40 But if they are in Parallel do I Divide each Resister like so R1=20 Divided by R2=20 then the Total Resistance is 1 Ohm am I right? Click to expand... . For only two resistors, the unreciprocated expression is reasonably simple: So R1//R2, 20//20 is 10 ohms. "//" = parallel (1/20)+(1/20)=0.05+.05=0.10= (1/0.1) =10