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Series and Parallel

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biferi

Member
I know if I have say 3 Resisters in Series and I know they are
R1=20 Ohm and R2=20 then the both of them will be 400 Ohm.

But if they are in Parallel do I Divide each Resister like so
R1=20 Divided by R2=20 then the Total Resistance is 1 Ohm am I right?

Please keep it simple but tell me in your own words.
Thank you.
 

ronsimpson

Well-Known Member
Most Helpful Member
I know if I have say 3 Resisters in Series and I know they are
R1=20 Ohm and R2=20 then the both of them will be 400 Ohm.
20+20=40
But if they are in Parallel do I Divide each Resister like so
R1=20 Divided by R2=20 then the Total Resistance is 1 Ohm am I right?
301px-Resistors_in_parallel.svg.png
0f67a9d6ad548b23212a3161ebabcf51.png.
For only two resistors, the unreciprocated expression is reasonably simple:

f5f541d249c3af1c6a5567bbaa7002b5.png
So R1//R2, 20//20 is 10 ohms. "//" = parallel

(1/20)+(1/20)=0.05+.05=0.10= (1/0.1) =10
 
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