Resistance measurement using multimeter

[vinodquilon]

Resistance/Voltage measurement using multimeter

Consider the below circuit with 28V supply and 5A load.

What voltage would I expect when I connect a multimeter between A & B ?
V(AB1)= V(R6)+V(R8)+V(R9)


What voltage would I expect when I connect a multimeter between C & D ?
V(CD1)= V(R7)+V(R8)+V(R10)

Consider the second circuit.

What voltage would I expect when I connect a multimeter between A & B ?
V(AB2)= V(R6)+V(R8)+V(R9)


What voltage would I expect when I connect a multimeter between C & D ?
V(CD2)= V(R8)

Am I right ? And V(AB2)>V(AB1)

 

[JimB]

Am I right ?

Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors.

And V(AB2)>V(AB1)

Yes, if the load current is the same 5 amp.

JimB

 

[vinodquilon]

Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors.


Yes, if the load current is the same 5 amp.

JimB

It is an electronic load set at 5A Constant Current mode.

 

[canadaelk]

Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E

 

[vinodquilon]

Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E

Sorry, It is intended for voltage measurement not resistance.

 

[JimB]

Without resistor values you are wasting time and effort.

That was my initial reaction, until I read the question a second time.

As VQs question is written, you do not need to know the resistance values.

JimB

 

[JimB]

The question as written is vague and confusing, it would be much better if the thread title was simply:

Voltage measurement

And the words

What would I expect when I connect a multimeter between A & B ?

What voltage would I measure between A and B?

Only when you read the expression:

V(AB1)= V(R6)+V(R8)+V(R9)

does it become clear what the real question is.

JimB