Resistance measurement using multimeter

Resistance/Voltage measurement using multimeter

Consider the below circuit with 28V supply and 5A load.

What voltage would I expect when I connect a multimeter between A & B ?
V(AB1)= V(R6)+V(R8)+V(R9)


What voltage would I expect when I connect a multimeter between C & D ?
V(CD1)= V(R7)+V(R8)+V(R10)

Consider the second circuit.

What voltage would I expect when I connect a multimeter between A & B ?
V(AB2)= V(R6)+V(R8)+V(R9)


What voltage would I expect when I connect a multimeter between C & D ?
V(CD2)= V(R8)

Am I right ? And V(AB2)>V(AB1)

Am I right ?

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Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors.

And V(AB2)>V(AB1)

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Yes, if the load current is the same 5 amp.

JimB

JimB said:

Yes. Assuming that the impedance of the voltmeter is high compared with the values of the resistors.


Yes, if the load current is the same 5 amp.

JimB

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It is an electronic load set at 5A Constant Current mode.

Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E

canadaelk said:

Without resistor values you are wasting time and effort. The rest, once R values are given, is grade 5 arithmatic. E

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Sorry, It is intended for voltage measurement not resistance.

Without resistor values you are wasting time and effort.

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That was my initial reaction, until I read the question a second time.

As VQs question is written, you do not need to know the resistance values.

JimB

The question as written is vague and confusing, it would be much better if the thread title was simply:

Voltage measurement

And the words

What would I expect when I connect a multimeter between A & B ?

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What voltage would I measure between A and B?

Only when you read the expression:

V(AB1)= V(R6)+V(R8)+V(R9)

Click to expand...

does it become clear what the real question is.

JimB