So say we have x²-2. Is there a way to rid the square and keep the binomial true? In other words we need to keep it X+/-? in the for x+? or x-? but do away with the square.
So say we have x²-2. Is there a way to rid the square and keep the binomial true? In other words we need to keep it X+/-? in the for x+? or x-? but do away with the square.
So say we have x²-2. Is there a way to rid the square and keep the binomial true? In other words we need to keep it X+/-? in the for x+? or x-? but do away with the square.
If you can accept an approximation, you can linearize about a selected point.
Use a Taylor Series Expansion, but take only the first two terms ..... Taylor series - Wikipedia, the free encyclopedia
..... If your independent variable value is too far removed from the evaluation point, the approximation won't be valid. ... Just depends on what your objective is.