Hi,
I also interpreted this question to mean a voltage gain because it appears to be set up for that...an AC voltage amplifier.
Using a model of the transistor as a current controlled current source with a constant voltage base emitter diode, i found the following equations using nodal analysis:
Vc=(R2*(R1*(V4+I1*R4)+Rin*(V4+I1*R4)-Vin*B*R4+Vd*B*R4)+R1*(Rin*(V4+I1*R4)+Vd*(B+1)*R4)+Rin*Vin*R4)/(R1*((B+1)*R4+Rin)+Rin*R4+(R1+Rin)*R2)
Vb=(R1*(Rin*(V4+I1*R4)+Vd*(B+1)*R4)+Rin*Vin*R4+(Vd*R1+Rin*Vin)*R2)/(R1*((B+1)*R4+Rin)+Rin*R4+(R1+Rin)*R2)
where
V4 is the collector voltage with zero input signal,
Rin is the transistor input resistance in series with the base emitter diode,
I1 is the 1ma current source,
B is the beta of the transistor,
R1 is the input 20k resistor,
R2 is the 200k resistor,
R3 is the 225 Ohm resistor,
R4 is the 20k load resistor,
Vd is the base emitter diode drop (which can be non linear if needed),
and assuming the two capacitors have zero impedance at the operating frequency.
Using this formula i found the voltage gain to be 7.33, but my guess was higher around 8 due to the 20k on the input and 200k feedback resistor, and the fact that the 225 ohm resistor also provides some negative feedback. That was also using a transistor with a gain of 49, and the transistor was biased pretty hard for this circuit, and Vd was held constant for simplicity. I suspect it could be higher with a different bias too.