programming PIC16 with ICD2 ?

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Anthony_87

New Member

• May 17, 2010

• #1

Dear all,

I have an ICD2, and I use it to Debug/Program development boards based on the PIC18 family. so I was wondering, can I use the ICD2 to Debug/Program the 16 family, beginning with the smallest devices like PIC16F84 ... to reach the more complex ones like 16F877 ??
if yes, how can it be used? any link or Blog will definitely help, thanks in advance.

Best Regards!

 

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Pommie

Well-Known Member

Most Helpful Member

• May 17, 2010

• #2

You just need a 16 series development board or connect one up on a breadboard.

Mike.

 

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Anthony_87

New Member

• May 18, 2010

• #3

do u know any link that provides an efficient circuit that allows me to program PIC16 family using ICD2 ?

Best Regards

 

P

Pommie

Well-Known Member

Most Helpful Member

• May 18, 2010

• #4

You just connect the ICSP connections and you're good to go.

Mike.

 

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Anthony_87

New Member

• May 18, 2010

• #5

The Pic18 family include PGC and PGD in their pinout, unlike the small PIC16... Im not sure how to do the connection from the RJ11 module of the ICD2 and the lets say the PIC16F84 itself ... how should it be done ? thx

 

blueroomelectronics

Well-Known Member

• May 18, 2010

• #6

The ancient 16F84 does not support the ICD2. The slightly newer 16F84A does.

 

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Anthony_87

New Member

• May 18, 2010

• #7

The 16F84A dont include PGC and PGD in its pinout !! so how to connect it with the ICD2's interface (RJ11), thats where im lost !!
thx

 

blueroomelectronics

Well-Known Member

• May 18, 2010

• #8

RB6 & RB7 are the ICD pins on most baseline PICs

 

Mickster

Well-Known Member

Most Helpful Member

• May 18, 2010

• #9

Look at the datasheet for your intended target, specifically the "Pinout description table".

For the 16F84A datasheet I have to hand, as Bill notes, RB6 & RB7 are respectively labelled as "Serial programming clock" and "Serial programming data".

PGC is your "Serial programming clock"
PGD is your "Serial programming data"


HTH.

 

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Anthony_87

New Member

• May 18, 2010

• #10

ok! im good to go now, thank u all