My problem is R1 gets damn hot when the pot is turned to closing on 0. Also, with a multimeter attached to the vout, I'm getting 23.5v +-, even when adjusting the pots very slowly.
Here is a pic of my project, there is no track breaking. **broken link removed** **broken link removed**
Here is another ref circuit I used...
**broken link removed**
Is there a way to work out how much current is flowing through the resistor, because as far as my Multisim goes it says around 0.01A on an meter put between the resistor and Vout.
R1 has 1.25V across it. Then if it is 240 ohms (used with a more expensive LM117) then the current in R1 and R2 is 1.25V/240 ohms= 5.2mA.
If R1 is 120 ohms for an LM317 then the current is 10.4mA. The current is actually slightly higher because the current from the ADJ pin is 50uA to 100uA and is also in R2.
I agree that one of your diodes is connected backwards.
There's nothing wrong with the diagram. All you have to do is to replace R2 220R 0.25w resistor with a 0,5w 220R resistor. Just remember to add the 2200uF cap in parallel with C1 if you use a transformer
R1 must not be higher than 120 ohms for the less expensive LM317 or the output voltage will rise without a load.
R1 must not be higher than 240 ohms for the more expensive LM117.
There is no 220 ohm resistor, it is wrong at 240 ohms.
If R1 is 220 ohms then it dissipates only 0.007W so a tiny 0.1W resistor is fine and a big 1/2W resistor is not needed.
R1 must not be higher than 120 ohms for the less expensive LM317 or the output voltage will rise without a load.
R1 must not be higher than 240 ohms for the more expensive LM117.
Can you show me where you get 220 ohm from? I really want to learn as the datasheet gives a 240 ohm example, if you can show me where you get the values from and the calculation you use I'd really appreciate it. Or even refer me to more documentation to read.
As usual, Scrooge is a bit dogmatic. It doesn't matter much if R1 is anywhere from 100 to 240 Ohms. The resistor value stems from the minimum load current spec for the LM317, and to a lesser amount, that the current through R1 be large compared to the Adj pin current.
If you know a priori that the load current will always be much over the min. current specified for the LM317, then you can raise the impedance of the voltage divider. I have used as much as 1K for R1. At 1K, the regulation begins to suffer a bit, because the Adjust pin current starts approaching a larger fraction of the current through R1.