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hi I tray to drive stepper motore using PIC and my problem now that the uln2003 ic not work propably . I connect its PIN8 to GND and PIN12 TO +12 V but when I put the 5V in the input pin i get only 0.6 v in the out put pin !!!!??? your help please
Rated voltage : 5VDC
Number of Pole : 4
Speed Variation Ratio : 1/64
Stride Angle : 5.625° /64
DC resistance : 200Ω±7%(25℃)
Idle In-traction : Frequency >600Hz
Idle Out-traction : Frequency >1000Hz
In-traction Torque >34.3mN.m(120Hz)
Self-positioning Tor >34.3mN.m
insulated resistance >10MΩ(500V)
insulated electricity power :600VAC/1mA/1s
Insulation grade :A
Rise in Temperature <40K(120Hz)
Noise <40dB(120Hz,No load,10cm)
how many pins does the Stepper have. This is key to know if it is bipolar or unipolar. I am guessing by 4 poles it has 5 pins in which case it would be a unipolar?
if it is unipolar you connect the common to the 12v source that also connects to pin9(clamp). the outputs of the stepper goes to pins 16-12(outputs 1,2,3,4 respectivly). the inputs go to pins 1-4(1,2,3,4 respectivly). Pin 8 goes to ground
If the stepper is burned up because of 12 volts then the ULN2003's output will be 0 volts only. With a meter check if there is resistance in the stepper.
I don't think running a 5 volt stepper on 12 volts will do any harm, the steppers on my cnc are rated at 2.3 volt and I run them at 30 volts....... Also 5 and 6 wire unipolar steppers can be run as bipolar by simply leaving the centretap (voltage wire/s) unconnected. I have also tested this with my 6 wire steppers and found they are more powerful running on bipolar.
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