problem in transition from phasor to normal..

[nabliat6]

**broken link removed**

oiler formula says
cosx+isinx

but here they multiply by minus the imaginary part of the phasor representation
the coefficient of sine is minus the imaginary part
why??

 

[MrAl]

Hi there,


Note that:
-3*j amps

converts to:
3*sin(wt)

It does *NOT* convert to:
-3*sin(wt)

Note:
(-3*j)*j*sin(wt)=3*sin(wt)

ie:
(-3*j)*j=3

 

[nabliat6]

thanks jk

 

[Hayato]

It would be much easier if you post the whole problem. From where did you get the sine and cosine arguments?

Observe that sine comes with j and cosine comes alone.

So, you could consider, sinx = -3R/[R²+(1/2C -2L)²], and cosx = (2L-1/2C)/[R²+(1/2C -2L)²]