Hi Overclocked,
Thks for data,
Shame you are not going to build the circuit yourself, but you are going the best way. That commercial SMPS looks good and at 16 bucks is a bargain.
By the way I have now analysed your requirements in detail including the NCL30160 data sheet- useful chip.
I now have 5 aproaches: 3 series preregulators, one using a power a PMOSFET and two using power BJTs; the originally posted shunt regulator, which inspite of the comments by chemilec and my initial panic, is fine; and a method of modifying the brige circuit to produce a peak voltage of 39V.
Why is the shunt design OK? It is Ok because:
It only takes current when the supply line is 37V and over. At 37 V input and 1A current into your high power LED the NCL30160 will be drawing 1.08 A. The impedance of the rectifying circuit is 19R5, so the 80 mA over 1A will drop the rectifier voltage to 41.5-1V56= 39V94. So, in theory, the circuit will work within design spec without any preregulation because the NCL30160 will take 40V (in practice it is bound to take more than that). But the shunt regulator is set at 37V, so it will take enough extra current to realise a further voltage drop of 39V94 - 37V= 3.94V. Thus the shunt regulator will take 3.94/19R5= 202mA.
This would be fine but could be reduced greatlly by setting the regulation voltage to 39V insted of 37V, which would still suit the NCL30160. The shunt regulator would be required to drop the voltage 39V94-39V=0V94. Thus the current that the shunt regulator would have to sink would be 0V94/19R5= 48.21 mA.
Because of the characteristics of a bridge rectifier, transformer and reservour capacitor the situation is more complex as you need to take ripple voltage into account. This means that the shunt regulator would be taking far less curent. I recon that a 4m7F capacitor would have a 2V peak to saw tooth ripple wave form which would probably be optimum.
The one drawback with the shunt regulator is that if the load were removed it would still maintain the output voltage at 37V. To do thhis it would need to drop the rectified of load voltage of 61V by 24V. From this the current drawn by the shunt regulator would be 24/19.5= 1.23A. No different to normal operation. The power transistor would be dissipating 1.23A* 37V= 45.51W: not the end of the world. A simple addition to the circuit could cut this to zero, but as you are abandoning this approach I won't take it any further.
The LM317H approach appeals but by the time you have taken the drop out voltage into consideation, thye ripple v0oltag and the thermal shut-down it seemed problamatic. But I havent done a detailed analysis so that is only my gut feeling.
The top contender, which I have just finished in hand sketch form, is the PMOSFET serial preregulator.
Nice talking to you- especially your presentation of data.
spec