that's assuming the outputs in those chips are EF.... they could very likely be CFP, in which case they swing to within 0.7V of each rail.
Follow along with the video below to see how to install our site as a web app on your home screen.
Note: This feature may not be available in some browsers.
That's true which is why car audio makers used to design systems running a pair of 3.2 Ohm speakers in parallel to get 1.6 Ohm effective impedance. We made power IC's that could source peak currents up to a about 6A to be able to drive signals into those loads.The battery can supply 10.8V at 4.4A for one hour which is 48Whr, not 90Whr.
I have never seen an amplifier that has an output power as high as 30W with a supply voltage as low as 10.8V. A bridged car radio amplifier will have an output power of only 8.6W into a 4 ohm speaker at clipping when its supply voltage is only 10.8V.
Do you see the two yellow and a black wire in Photo0063.jpg .
Cut them on half or neerer to transformer
(the big metal cube thing). Take the transformer out (since you dont need it anymore).
You can use two 12V batteryes (which wont give full poWer)
or maybe use power(hand)tools battery packs which are 14.4V or more.
Connect plus of one bat to minus of the other and connect this to black wire.
Now you have free unconected two yellow wires and UNCONNECTED plus of
one bat and UNCONNECTED minus of the other. Connect yellow#1 to unconnected plus and the
yellow#2 to unconnected minus.If it dont work exchange #1 and #2
(yellow#1 to minus and yellow#2 to plus).
Your amp is linear which means it will waste energy.
Most battery hand tools have PWM (Pulse Width Modulation)
which makes bat last longer.
Edit:
But if the transformer has more than 5 wires coming out of it don't do this.
so the voltages you need to supply to the amplifier are +/-16V. it will probably still work ok on +/-12V, but with less power. with +/-16V you get about 15W into 8 ohms, with +/-12V, you will get 9W into 8 ohms. that's a difference of about 2db.