Those capacitors are simply decoupling capacitors. There doesn't seem to be anything about their arangement that could be described as a charge pump.
In the circuit that you posted, the current limit is set at 75mV / 4m
hm:
(75mV comes from the LT1735 data sheet, the 4m
hm: from your circuit)
That is just under 20 A which does seem high for a 2.6A circuit, even for 6 A. (I am not sure which value your circuit is rated at as both values appear on the diagram)
It also seems too high for the inductor if I read **broken link removed** correctly.
The current turns on and off at about 300 kHz, so the capacitors need to store 20/300000 = 67:mu: C of charge so 50 :mu:F near Q18 seems a good idea, as that should keep the ripple down to about a volt. There is also the ESR of the capacitors to consider. The ESR must be kept low to keep the resistive portion of the ripple low.
With all those capacitors, chosen to reduce the ripple, the inrush current will be big if the circuit is to work correctly. I wouldn't reduce the capacitors unless you redesign the whole circuit.
If you want to reduce the inrush current, limit the rate of rise of input voltage if you can, or have a resistor in series that is bypassed once the capacitor are charged.