J JeanTech Member Mar 21, 2014 #1 Good day How can I calculate the value of the capacitor required to correct the circuits power factor to 1? Thanks in advance JeanTech Attachments power_factor.png 7.5 KB · Views: 276
Good day How can I calculate the value of the capacitor required to correct the circuits power factor to 1? Thanks in advance JeanTech
Miles Prower Member Mar 21, 2014 #2 Looks easy enough. A PF= 1.0 implies a purely resistive load. If the load is the series inductor and resistor, then: Zl= 7.0 + j26.39 R Since it's a parallel connection, you need the equivalent admittance of the load: Yl= 1/Zl Yl= 1/(7 + j26.39)= 9.39E-3 - j35.4E-3 A/V Knowing you have a Bl= -j35.4E-3, you need a Bc= j35.4E-3: Bc= wC: C= Bc/w= 35.4E-3/(2pi * 60)= 93.9uF
Looks easy enough. A PF= 1.0 implies a purely resistive load. If the load is the series inductor and resistor, then: Zl= 7.0 + j26.39 R Since it's a parallel connection, you need the equivalent admittance of the load: Yl= 1/Zl Yl= 1/(7 + j26.39)= 9.39E-3 - j35.4E-3 A/V Knowing you have a Bl= -j35.4E-3, you need a Bc= j35.4E-3: Bc= wC: C= Bc/w= 35.4E-3/(2pi * 60)= 93.9uF