Making a 50a+ buck converter.. maybe

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Tcmtech, in again with the MikeMi haha.
I'd asked the same question previously and Mike added an rc to the pwm circuit he'd already drawn for me. It didnt work though, the readout I have has to measure load resistance after the rc. Only did a quick test but the rc was obviously adding resistance. Perhaps I got it wrong? I'll test that again to be sure.
The only readout I've found that displays the info I need has two inputs, Vin and Vout. Vin displays battery voltage, on the Vout side it measures voltage under load and the loads resistance. It then calculates actual amps and wattage being used based on those. All are displayed on screen. It won't work with N channel mosfets either, not sure how but it makes the circuit so its permanently on.
As this is a fairly powerful lipo powered handheld device I'm making, I need to build in a modicum of safety. Knowing resistance, current and the amp limit of the battery is paramount. Which goes back to my last post asking if v/ir math still applies to the circuit, the math reads like the available current drops a higher percentage than voltage does pro rata. given my display is a safety measure it needs to read true.

ChrisP58. You know when the penny drops and you get that moment of clarity.. almost had that while reading your post I'm sure there's something I can take from that, time for a Google. Thanks buddy.
 


Hello,

The load current simply follows Ohm's Law: I=V/R
If you turn the voltage down, the current follows in proportion.
 


What?

Drinking and keyboarding?
 
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