LPC 2148 Serial Communication

Hi.. I've written a code to transmit a character to PC using UART0. But, however, the hyperterminal is blank.
Why is this happening?
My code is as follows:

But if I modify d same code for UART1 it works fine.. Its only giving a problem with UART0..

Is this happening because I'm using UART0 as ISP port to program my chip? I use flash magic & use the DTR & RTS to control the RST & ISP pins. So is it possible that my port is stuck in ISP mode & is that the reason why its not functioning as a normal UART?

I'm really confused..

Twisted_transistor said:

But if I modify d same code for UART1 it works fine.. Its only giving a problem with UART0.. پروژه هاي الکترونيک کنترل مانيتورينگ اتوماسيون صنعتي ارایه انواع پروژه هاي صنعتي آزمايشگاهي دانشگاهي تحقيقاتي automasys.wordpress.com انواع میکروکنترلرهاي میکروچيپ اتمل اينتل فيليپس AVR ARM LPC STM32 PIC dsPIC 8051 8086 z80 انواع اينترفيس و پروتکل هاARM AVR PIC MicroController Electronic Project GPRS GSM USB BlueTooth Ethernet Network CAN I2C SPI RS485 Automation PLC پروژه الکترونيک میکروکنترلر آرم 8051 اتمل فيليپس میکروچيپ Interface اينترفيس ويژوال استاديو Visual Studio 2010 C# VB.Net Protel DXP Altium Eagle PCB SPICE PSPICE HSPICE ADS OrCAD Silvaco
Is this happening because I'm using UART0 as ISP port to program my chip? I use flash magic & use the DTR & RTS to control the RST & ISP pins. So is it possible that my port is stuck in ISP mode & is that the reason why its not functioning as a normal UART?


I'm really confused..

Click to expand...

Have you also changed PINSEL register to a proper value or just you have changed everything 1 to 0?

How about using:

U0

how to use uart interrupt in lpc2148?
how to receive char through interrupt in lpc2148?tell me what is wrong in this code.received char i've to transmit again but it is not working.
#include <lpc214x.h>
void init_UART0(void)
{
VPBDIV=0x01;
PINSEL0|=(1<<0)|(1<<2);
U0LCR=0x83;

/*to set baudrate using formula, load below registers
.....................................................................................................*/
U0DLL=78;
U0FDR=0x28;
U0LCR=0x03;
U0IER=0x01;

VICIntSelect=0x00;//IRQ interrupt
VICVectAddr0=(unsigned long)UART0_isr;//isr assigned to 0th slot
VICVectCntl0=0x26;//vector interrupt enable & UART0 select
VICIntEnable=(1<<6);//enable interrupt

}

void Transmit(unsigned char ch)
{
while(!(U0LSR & 0x20)); //check THO is empty or not
U0THR=ch;
}

void UART0_isr(void)__irq
{
unsigned char p;
p=U0RBR;
Transmit(p);
VICVectAddr0=0x00;//clear address register

}
int main()
{
init_UART0();
while(1);
}

it seems that your code is correct . if you are using P0.1 for ISP programing, you must remove the pull up resistor on this pin.