If you look on page 3, where it lists 25 Ma as typical output short circuit current. Going one step further and looking on page 1 of the schematic it shows Q14 with a 25 ohm resistor between the base and emitter of Q14. It is my understanding that this will limit the output current. Using ohms law I=E/R. Since Vbe=0.7 volts to turn it on then
I=0.7/25 or 28mA. The actuall current depends on several factors, one is the actual value resistor R9. I would determine what the output voltage is going to be and use the 25 Ma figure to calculate the resistor in question.