how are you going to drive the LED? via a transistor? just use two stages. or use a divider for the transistor input. where you place the LDR in the divider determines how it turns on the transistor.
Like I said, it's a VERY poor circuit, and won't work at all well - an opamp will make a proper circuit, or you could improve it by adding a second transistor and making a schnitt trigger.
Cant you do it by yourself ? Its the first circuit in college basic electronics.what's the transistor & supply voltage you use? You dont like to add an IC for this isn't it? even you can add a another transistor for the circuit & check.do it yourself....
Electronics is a new field for me, the reason why I ask is because I don't know. And nothing I find on any search engine comes close to the information provided by those in the know.
I don't use IC's in any circuits, because I don't currently understand them completely. I work with what I understand.
At the moment, I have a limited supply of components, none of which are IC's, a few simulating programs and a breadboard.
With the help of others I've been teaching myself.
Very true - or the top transistor will blow - it's also more usual to use two NPN transistors with the emitters connected together for a schmitt trigger.
Here's the circuit I normally use for this kind of thing, you can replace the PNP transistor with a p-channel MOSFET and 1M pull-up resistor and it can switch larger loads without requiring a relay.